Torque and Chrome

The bolts on a car wheel require tightening to a torque of 90 N·m.?

If a 30 cm long wrench is used, what is the magnitude of the force required when the force applied at 53° to the wrench? 190 N 380 N 19 N 38 N can someone show me how to do this please :)

Public Comments

1. Torque is the cross product of force and distance. Therefore: torque=Fdsin(theta) 90=F(0.3)sin(53) F=375 N B hope this helps!!
2. just look at the dimensions (this is called dimensional analysis) and see if they cancel to get you the desired result. torque is in N-meters (that is newtons x meters). How do you get that to just newtons? By dividing by meters. so: 30 cm = 0.3 meter 90 newton-meters / 0.3 meter = 300 Newtons That is if everything is normal. But you have the 53º angle. That means not all of the force is at right angles to the wrench, where it has to be for torque. Looking at the geometry, sin 53 = 0.8, and that is the correction factor. The force has to be larger than 300, so that the component normal to the wrench is 300. And that would be 300/0.8 = 375 N Your second answer is closest. ,