Torque and Chrome

What is the force exerted on the wrench?

Torque has a magnitude of 80 N·m. Using the data in the figure, determine the magnitude F of the force that you must exert on the wrench. The wrench is .28 meters and pointed 50.0 degrees Northwest above the horizontal. The Torque is 80 Nm. I know T=Force x lever arm, but I forgot how to find the lever arm length. Can someone please explain?

Public Comments

1. The lever length to calculate with will be shorter than .28m. If you sketch a vertical line as your torque centre, then another line from it at 90 deg. to it, then from the intersection, a 3rd. line at 50 deg. to the horizontal line, its length representing .28 metres, and from the end of that, sketch another vertical line to intersect the horizontal line. You will have a right triangle, a known angle, and a known length hypotenuse. You need to calculate the length of the base, which is the arm length you need. Cos 50 deg = A/H, = .6428 H. H being .28m, = .179984 (say .18)m.