Torque and Chrome

Converting foot pounds to inch pounds on a torque wrench? I'm trying to put a new head gasket on my outboard. I don't have a inch pound torque wrench. Can I convert my lbs to get close to this job. I need 215 inch pounds per square inch., what would I set my foot pound torque wrench too?

Where can I buy an inch pound torque wrench? I have tried automotive stores such as Kragens, Autozone, etc. I have also tried department stores such as Home Depot, Sears...

How many inch pounds does it take to make a foot pound? I am trying to tighten a bolt to a a 11 foot lbs,and all I have to work with is a inch pound torque wrench.

Can you convert a torque wrench from inch pounds to foot pounds? If I need to torque something to 16 Ft pounds, can I use a torque wrench that measures "inch" pounds? If so, how do I convert that?

Torque Wrench? Can a Ft. Pounds torque be used to tighten something that needs Inch Pounds? like say i need to tighten a bolt 200 inch pounds that would be almost 17 foot pounds is that going to work or do i need the inch pounds torque wrench to do this ?

how do i convert inch pounds to foot pounds on a torque wrench, thanks ?

How important is appyling the right amount of inch pounds of torque to my base screws and rings? Im talking about when mounting my scope. Can I do without a torque wrench?

Is it possible to convert inch pounds into foot pounds so I can use the torque wrench I have?

find a torque wrench that reads in inch pounds? its for working on bikes I havent found one as of yet

To start rebuilding engines. What is the best range for torque wrenches? I want to buy some junker cars and try to get them running so i can eventually do it professionally (engine repair for coupes, sedans, SUVs, passenger vehicles in general). But I don't have a lot of start-up cash so what would be the best range for a torque wrench? 80-400ft. lbs.? 50-250ft. lbs.? Should I get a torque multiplier? What about the inch pounds torque wrenches? I want to work on foreign cars so should I get a metric wrench or just convert the measurements? I also want to make high performance upgrades like adding super and turbochargers and work with aluminum blocks. Does that mean I need to get a very costly torque wrench? Is there a book I can purchase with all of this information?

A driver must change a tire that has a stuck lug nut. A torque of 288 inch-pounds is required to free the? A driver must change a tire that has a stuck lug nut. A torque of 288 inch-pounds is required to free the nut. How much force must be exerted at the end of a 24-inch-long wrench to accomplish the task?

i need to toque a bolt to300 foot pounds and have no torque wrench. Would it not be the same as 200 pounds on? would it not be the same as 200 lbs on the end of an 18 inch wrench? Thanks for the confirmation

How do you use a dial torque wrench? Has Newton meters and inch pounds. Is it as simple as setting the pointer to the number and stopping when I reach that spot?

Motorcycle spark plug torque.? According to my owners manual I should tighten spark plugs to 10 foot pound. My torque wrench is marked in inch pounds. Will that be 120 inch pounds equal 10 foot pounds of torque?

Torques wrench question? I have to take off my transmission oil pan and I also have to put it back. The torque spec of the bolts that hold the tranny oil pan is 65 inch-pound not foot-pounds. The problem is I couldn't find a torque wrench that has an inch-pound feature, only foot-pounds is available. Im thinking about converting 65 inch-pound into foot pound and this is what i came up with: 65 inch = 5.4166667 feet Is 65 inch-pound similar to 5.4166667 or 6 foot pounds? I'm not really good in math, please help. I mean torque wrench.

Inch pounds. to foot pounds.? There is a specification to tighten a series of bolts on my car to 22 inch pounds but my torque wrench measures in feet. I realize the simple conversion is 1 ft. = 0.833333333, but 22 inches converts to 1.8333333 ft. which is obviously too weak. I have to convert 22", 44", and 89". Can anyone help?

My repair manual quotes some specs in inch pounds (in-lbs) as opposed to foot pounds. How do I convert?j? My torque wrench does not read in "in-lbs". What for example is 150 in-lbs in foot pounds? My stablizer bar link nut torque spec is said to be 150 in-lbs. Why is it necessary to quote torque specs in both inch and foot lbs? How do I convert one to the other. Thanks much in advance. Jim Confused

I do not understand how to work this work/ torque problem? I am confused? I am confused at what the question is asking: A torque wrench with a 12 inch handle is used on a bolt. A torque of 264 inch-pounds is applied to the bolt. How much force is needed on the handle to reach this torque? ______ Pounds. You do not have to solve it just provide or help me to understand this question with a formula. What exactly is it asking here? force or torque? Can you provide and example or how to calcaulate this. Thanks, mj6118

Click type Torque Wrench, 5 ft lb??? I am going to change my tranny fluid and the transmission pan bolts require 60 inch pounds or 5 ft lbs. However, I can't find a click type torque wrench that goes down to 5 ft lbs. All I can find is ones that go down to 10 or 20 ft lbs. I saw one at sears that goes down to 0 but it wasn't a click type. I need one that has a twist type handle and clicks at the proper torque. Please suggest a good torque wrench for my needs. I have changed tranny fluid before, so I know what is involved. But I just lightly tightened the bolts before with no torque wrench. I just didn't know how its done professionally since I can't seem to find a torque wrench that goes down that far.

For mechs that know torque wrenches, which would you buy & trust? Snapon Torque Wrench, Adj. Click-type, U.S., Compact-Ratchet, 40-200 in. lb., 3/8" drive http://buy1.snapon.com/catalog/item.asp?P65=&tool=hand&item_ID=55249&group_ID=953&store=snapon-store&dir=catalog Sears GearWrench Micrometer Torque Wrench 1/4" Drive 30-200 inch pounds http://www.sears.com/shc/s/p_10153_12605_00993097000P?vName=Automotive&keyword=%22torque+wrench%22 This is primarily for a Yamaha motorcycle Was also considering a Stanley Proto thats miltary grade... http://www.stanleyproto.com/default.asp?CATEGORY=MICROMETER+TORQUE+WRENCHES&TYPE=PRODUCT&PARTNUMBER=J6061CX&strSiteName=PROTO&strDefaultCatalog=PROTO&SDesc=1%2F4%26quot%3B+Drive+40+-+200+in%2Flb.+Fixed+Head+Micrometer+Torque+Wrench

How to find Torque with this information? A student working on their car needs to tighten the mounting bolts to a specified torque. If the student is using a 9.4 inch long wrench and is applying 16.8 pounds of force, what torque in Newton-meters (Nm) are they appling to the bolts? That is the question I was given. I don't even know where to begin. Could someone help me out? I can maybe answer one of your questions in exchange.

alternator torque query? take an average a 24v alternator, can anyone tell me what the minimum alternator pully wheel rpm (revolutions per minute) would need to be for a constant power supply to be generated? I also need to find out what approximate torque is required to turn the pully - expressed in pounds per sq inch as per a torque wrench.

I need help with a Torque question? Torque is not to be confused with Work. a. It is the product of an applied force and the distance between ___________ and ____________. b. Mechanics must sometimes apply an exact amount of torque when tightening fittings. If the specification calls for no more than 180 foot pounds of torque and there is only a 8 inch wrench available, how much force must be applied to do the job properly? Please show work Thank you

Magnitude and direction of torque? FInd the magnitude and direcction of the torque. The wrench is 9 inches, the force is 40 pounds and the angle is 70 degrees.

Question on understanding torque? So im going to replace my water pump and im reading the repair guide and it says to tighten bolts to 15-22 ft. lbs. (20-30 Nm). so my questions are is it 15-22 pounds of torque? cause that doesnt seem to be that much. and if so why does it say ft and lbs? and im not planing on using a torque wrench very much so i was going to buy this cheap one (see link 1). will it do the job good? or the one in link 2. more expensive but seems worth it. http://www.amazon.com/Neiko-Classic-Needle-Style-8-Inch-2-Inch/dp/B0019VMI0Y/ref=pd_cp_hi_3 http://www.amazon.com/gp/product/B0031QPJZG/ref=cm_rdp_product

Water pump stud broke. Am I screwed? 1994 Geo Metro XFi. The lower left water pump mounting stud broke as I was trying to torque with a Powerbuilt click type torque wrench good for between 10-150 foot lbs. My manuals (cliton’s and mitchell’s) both said 115 Inch lbs for the torque spec. 115 inches pounds = 9.58333333 foot pounds. So, I figured it would be ok to just set the wrench for 10 ft lbs and I’d be ok, in fact it’s so close to 10 ft lbs, I don’t know why they didn’t just say 10 ft lbs. Unforntuately I didn’t have the right extension to get on that lower left nut and was forced to use my u-joint, which I know you’re not supposed to do, but it was exactly the right length and I held it perfectly straight with my other hand so I figured it would be just the same as a straight extension. It ended up breaking the stud. Now I’m not sure what to do. I can feel the stud sticking through the back side of the water pump mounting surface. Is the stud pressed into place? How do I get the stud out to change it? Where can I find a replacement stud? Thank you very much for your help.

Finding torque using cross product? The specifications for a tractor state that the torque on a bolt with head size 7/8 inch cannot exceed 200 food-pounds. Determine the maximum force F that that can be applied to the wrench so as not to exceed the limit.

How hard to change Ford 1992 E350 front brake lines? I have done the rest of the steel lines at one time or another but now I must change the front. I am ok with the drivers' side but where is the line that runs from the drivers side flexible line over to the passenger side? I cannot seem to see it. I am also ok with bleeding the lines and double flaring but the line location has me stumped. The line change is because the steel line in question split when I bled the left caliper. It was frozen and I changed it along with the rotor and pads. The right side is ok but I put the new pads on anyway like you are supposed to do. They also call for the spindle nut to be set at 75 ft/pounds, then backed off 1/2 turn, then retorqued to 17 to 25 inch pounds. Is all that really critical? When I removes the old rotor it seemed to have some lateral freeplay (1/16th ?). At this time I do not have a torque wrench that small. The inner and outer bearings are new. I did it the book way before but I do not want to buy a dial torque wrench($250). THANKS! Sorry I guess I should have added more detail. My master cylinder has two lines on it. One goes down to the anti lock module. From the module a single line goes to the back brakes. On the front brakes the other line comes down from the master cylinder to the the drivers side brake flexible hose. There is a double female connection on the one(non caliper) end of the hose. One connection is to the descending line from the master cylinder. The other connection is for a steel brake line crossing over to the right caliper. I am sure of this because the driver side hose has two steel brake lines on it and the passenger hose has only one steel line connected to it.

Physics question: Finding Force? A mechanic wants to apply the correct amount of torque when tightening a nut on a fitting. If the specification call for no more than 100 foot pounds of torque and he only has a 6 inch long wrench, how much force must he apply to do the job?

help needed in my project "compressed air driven vehicle" full information given? the engine of my proposed vehicle is a pneumatic impact wrench ,the one we see in automobile garages for turning nuts.. these are always run by a compressors operating parallely for the supply of compressed air ( fuel ).the specifications of the pneumatic wrench that is thought to be as the prime mover (engine) are.... 1.air consumption --- 6cfm(cubic feet per minute) 2.operating pressure ---6.2 bar (90 psi,pounds per square inch) 3.max torque --- 500 lb-ft (678N-m) 4.weight --- 4.6 Kg the project should not include a compressor ,instead vehicle should be incorporated with a air storage tank .so it is thought appropriate to use a well capacitated tank that can store compressed air at atleast 30 bar so that the vehicle could run some distance..say abt 400 to 500 meters. the storage tank specifications are diameter-40 cm length - 1 m (even though the tank has hemispherical ends the additional volume is not included) volume of cylinder= 3.14(pi) x rad^2 x length =3.14*.04*1=0.125cu m (cubic meter) 1cu m = 100 litre (lt)==>0.125 cu m = 125 lt (this 125 lt is the capacity of cylinder) the compressed air is thought to be stored in the tank at the pressure of 30 bar. so the total amount of air available is equal to 125 * 30 = 3750 lt ( this is called as total air capacity) but... the wrench does not run if pressure falls below 6.2 bar right!so the air capacity at this pressure ie 6.2 bar is 125 * 6.2 = 875 lt ( rounded to 875 ). so the total air available for the wrench to function is ( 3750-875 )lt = 2875 lt take it as 2800 lt (for minimum time for which the wrench can be operated) .the air consumption of wrench is 6 cfm = 171.4 lt/min.(round it of to 175 lt/min for min time)so the time for which the wrench can be operated is (2875 lt)/ (175lt/min)=16 minutes. the total work(W.A) that can be done with the compressed air in the tank is equal to (V * dp); V = capacity of cylinder & dp is the pressure difference i.e (30 bar - 6.2 bar)=23.8 bar.so W.A = 0.125 cu m * 23.8 bar = 297500N-m (bcoz 1 bar = 10 ^5 N/sq m).so work available W.A = 297500 N-m . now consider the total loads on vehicle 1.weight of structure of vehicle = 200 kg 2.wt of person = 100 kg 3.wt of cylinder = 125 kg ( i guess) 4.wt of wrench = 5 kg 5 weight of compressed air at 30 bar= 4.5 kg 6.extra fittings wt = 25 kg (say) total weight = 459.5 kg (say it as) 475 kg so this mass is acting vertically downwards in "y - axis" so the normal reaction (N) acting on vehicle is (m*g)==> 475 * 10 = 4750 N .THE VEHICLE HAS TO MOVE IN " X - AXIS " right! so it has to have a mininum force so as to overcome frictional force which is equal to ( u * N ); where u = coeff of friction between wheel and tyre .since the frictional force is rolling friction it is very less; also once it starts moving the frictional force ( F ) to be overcomed for the movement decreases the F = 0.15 * 4750 = 712.5 N say it 720 N. AM I right ??? does my pneumatic wrench helps in moving the vehicle ??? what i think is...... 1.the value of F is much less than 720 N when in motion.work = force * distance ;the above calculated work is equated to F * d (d = distance moved )force is 720 N so.... d = 297500/720 = approx 400 m . but in actual i thing it is still more cos of gear arrangement bcos of which speed increases and hence distance ,also it is rolling friction and not static so once the body is set to motion ,there is no need to apply 720 N even lesser force would be enough!! am i right???????????? 2.even though 3 gear shifts are proposed for speed increments of vehicle ,for convinience and for finding out whether the initial torque provided by wrench is sufficient in moving the vehicle , i assume that the wrench is directly coupled to axle by a gear arrangement such that the direction of rotation of the wrench's drive is turned by 90 degrees so that the axle rotates in the direction of rotation of wheels . ok!!!!! now due to such a SUN - PLANET gear arrangement let the torque fall to a value like.... say around 550 N-m (i.e from 678 N-m to 550 N-m )so now the axle is driving both the rear wheels with 550 N-m.this torque is constrained to the curcumference of axle only!!??? got ittt!!!! i mean ... torque = force * distance ok!!this force acts tangential to the axle's circumference and distance is equal to radius of axle ( say it .02 m) hence what i meant was the above torque is torque acting on axle only ; 3.the force required to move the vehicle overcomming the friction is 720 N which acts tangential to the rear wheels!!! am i right??????so the torque required to move vehicle is = ( 720 * radius of wheel ) ==> 720 N * 0.2 m = 144 N-m okkkk but the torque available at axle is 550 N-m i.e at distance of 0.02 m from center of axle ..so the torque with which the axle twists the wheel is equal to ????? it can be found from equation torque (T) = F * distance ==> T is directly proportional to distance ( radius) so Ta/ Ra = Tw/ Rw (Ta = torque at axle, Rw = rad of wheel ,Tw = torque at wheel ,Ra = radius of axle ); so 550/.02 = Tw/.2 ==> Tw=5500N-m;that is huge amount of torque is available for the movement; actual required torque is 144 N-m which is veryyyy small to what is available ,even if the torque required is more say around 300N-m ,it can also be overcomed . ?????? am i right ???????if not plsssss suggest meee and correct mee ?????? am i right ???????if not plsssss suggest meee and correct mee

How many inch pounds does it take to make a foot pound? I am trying to tighten a bolt to a 11 foot pound and all I have to work with is a inch pound torque wrench.

Torques wrench question? I have to take off my transmission oil pan and I also have to put it back. The torque spec of the bolts that hold the tranny oil pan is 65 inch-pound not foot-pounds. The problem is I couldn't find a torque wrench that has an inch-pound feature, only foot-pounds is available. Im thinking about converting 65 inch-pound into foot pound and this is what i came up with: 65 inch = 5.4166667 feet Is 65 inch-pound similar to 5.4166667 or 6 foot pounds? I'm not really good in math, please help. I mean torque wrench

VW Passat Anti Seize and Torque Wrench for Spark Plugs? Hi everyone I bought four NGK V-Power BKR6E spark plugs. And today I'm looking at installing them. What I'm wondering is if I should buy some Anti Seize to put on the plugs before I put them in? Also would it be needed to buy a Torque Wrench inch pounds or foot pounds to tighten the spark plugs? Or just go finger tight with a 1/4 to 1/2 turn with a ratchet. Thanks for the help. My car is a 2003 VW Passat 1.8t GLS.